Fifth American Chess Congress (1880)
The fifth American Chess Congress was held in New York on January 6–26, 1880 and won by Mackenzie (he beat James Grundy on tiebreak, 2–0). There were 10 players: Cohnfeld, Congdon, Eugene Delmar, Grundy, Judd, Mackenzie, Mohle, Ryan, Sellman, and Ware.
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Player 1 2 3 4 5 6 7 8 9 10 Total 1 George Henry Mackenzie (USA) xx 0½ 10 ½½ ½1 11 11 11 1½ 11 13½ 2 James Grundy (USA) 1½ xx ½½ 10 1½ 11 1½ 01 11 11 13½ 3 Charles Moehle (USA) 01 ½½ xx 0½ 1½ 10 11 11 11 11 13 4 Alexander Sellman (USA) ½½ 01 1½ xx 10 1½ 11 0½ 11 11 12½ 5 Max Judd (USA) ½0 0½ 0½ 01 xx ½1 11 11 01 11 11 6 Eugene Delmar (USA) 00 00 01 0½ ½0 xx 11 11 ½1 11 9½ 7 John Ryan (USA) 00 0½ 00 00 00 00 xx 11 01 11 5½ 8 Preston Ware (USA) 00 10 00 1½ 00 00 00 xx ½1 1½ 5½ 9 James Adams Congdon (USA) ½0 00 00 00 10 ½0 01 0½ xx 00 3½ 10 Albert Cohnfeld (USA) 00 00 00 00 00 00 00 0½ 11 xx 2½
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