Truncated Icosahedron - Area and Volume

Area and Volume

The area A and the volume V of the truncated icosahedron of edge length a are:

\begin{align} A & = \left ( 20 \cdot \frac32\sqrt{3} + 12 \cdot \frac54\sqrt{ 1 + 2/\sqrt{5}} \right ) a^2 \approx 72.607253a^2 \\ V & = \frac{1}{4} (125+43\sqrt{5}) a^3 \approx 55.2877308a^3. \\ \end{align}

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