The Supply of Representations
So what are the reps of Diffx1(M)? Let's use the fact that if we have a group homomorphism φ:G → H, then if we have a H-representation, we can obtain a restricted G-representation. So, if we have a rep of
- Diffx1(M)/Diffxn(M),
we can obtain a rep of Diffx1(M).
Let's look at
- Diffx1(M)/Diffx2(M)
first. This is isomorphic to the general linear group GL+(n, R) (and because we're only considering orientation preserving diffeomorphisms and so the determinant is positive). What are the reps of GL+(n, R)?
- .
We know the reps of SL(n, R) are simply tensors over n dimensions. How about the R+ part? That corresponds to the density, or in other words, how the tensor rescales under the determinant of the Jacobian of the diffeomorphism at x. (Think of it as the conformal weight if you will, except that there is no conformal structure here). (Incidentally, there is nothing preventing us from having a complex density).
So, we have just discovered the tensor reps (with density) of the diffeomorphism group.
Let's look at
- Diffx1(M)/Diffxn(M).
This is a finite-dimensional group. We have the chain
- Diffx1(M)/Diffx1(M) ⊂ ... ⊂ Diffx1(M)/Diffxn(M) ⊂ ...
Here, the "⊂" signs should really be read to mean an injective homomorphism, but since it is canonical, we can pretend these quotient groups are embedded one within the other.
Any rep of
- Diffx1(M)/Diffxm(M)
can automatically be turned into a rep of
- Diffx1/Diffxn(M)
if n > m. Let's say we have a rep of
- Diffx1/Diffxp + 2
which doesn't arise from a rep of
- Diffx1/Diffxp + 1.
Then, we call the fiber bundle with that rep as the fiber (i.e. Diffx1/Diffxp + 2 is the structure group) a jet bundle of order p.
Side remark: This is really the method of induced representations with the smaller group being Diffx1(M) and the larger group being Diff(M).
Read more about this topic: Representation Theory Of Diffeomorphism Groups
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