Extreme Value Theorem
To show that a real continuous function f on has a maximum, let N be an infinite hyperinteger. The interval has a natural hyperreal extension. The function ƒ is also naturally extended to hyperreals between 0 and 1. Consider the partition of the hyperreal interval into N subintervals of equal infinitesimal length 1/N, with partition points xi = i /N as i "runs" from 0 to N. In the standard setting (when N is finite), a point with the maximal value of ƒ can always be chosen among the N+1 points xi, by induction. Hence, by the transfer principle, there is a hyperinteger i0 such that 0 ≤ i0 ≤ N and for all i = 0, …, N (an alternative explanation is that every hyperfinite set admits a maximum). Consider the real point
where st is the standard part function. An arbitrary real point x lies in a suitable sub-interval of the partition, namely, so that st(xi) = x. Applying st to the inequality, we obtain . By continuity of ƒ we have
- .
Hence ƒ(c) ≥ ƒ(x), for all x, proving c to be a maximum of the real function ƒ. See Keisler (1986, p. 164).
Read more about this topic: Non-standard Calculus
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