Example
In the following example there are seven tasks, labeled A through G. Some tasks can be done concurrently (A and B) while others cannot be done until their predecessor task is complete (C cannot begin until A is complete). Additionally, each task has three time estimates: the optimistic time estimate (O), the most likely or normal time estimate (M), and the pessimistic time estimate (P). The expected time (TE) is computed using the beta probability distribution for the time estimates, using the formula (O + 4M + P) ÷ 6.
| Activity | Predecessor | Time estimates | Expected time | ||
|---|---|---|---|---|---|
| Opt. (O) | Normal (M) | Pess. (P) | |||
| A | — | 2 | 4 | 6 | 4.00 |
| B | — | 3 | 5 | 9 | 5.33 |
| C | A | 4 | 5 | 7 | 5.17 |
| D | A | 4 | 6 | 10 | 6.33 |
| E | B, C | 4 | 5 | 7 | 5.17 |
| F | D | 3 | 4 | 8 | 4.50 |
| G | E | 3 | 5 | 8 | 5.17 |
Once this step is complete, one can draw a Gantt chart or a network diagram.
Read more about this topic: Gantt Chart
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