Dominated Convergence Theorem - Discussion of The Assumptions

Discussion of The Assumptions

The assumption that the sequence is dominated by some integrable g can not be dispensed with. This may be seen as follows: define ƒ_n(x) = n for x in the interval (0, 1/n] and ƒ_n(x) = 0 otherwise. Any g which dominates the sequence must also dominate the pointwise supremum h = sup_n ƒ_n. Observe that

$\int_0^1 h(x)\,dx \ge \int_{1/m}^1{h(x)\,dx} = \sum_{n=1}^{m-1} \int_{\left(\frac1{n+1},\frac1n\right]}{n\,dx} = \sum_{n=1}^{m-1} \frac{1}{n+1} \to \infty \quad \text{as }m\to\infty$

by the divergence of the harmonic series. Hence, the monotonicity of the Lebesgue integral tells us that there exists no integrable function which dominates the sequence on . A direct calculation shows that integration and pointwise limit do not commute for this sequence:

$\int_0^1 \lim_{n\to\infty} f_n(x)\,dx = 0 \neq 1 = \lim_{n\to\infty}\int_0^1 f_n(x)\,dx,$

because the pointwise limit of the sequence is the zero function. Note that the sequence {ƒ_n} is not even uniformly integrable, hence also the Vitali convergence theorem is not applicable.

Read more about this topic: Dominated Convergence Theorem

Famous quotes containing the words discussion and/or assumptions:

“There exist few things more tedious than a discussion of general ideas inflicted by author or reader upon a work of fiction.”
—Vladimir Nabokov (1899–1977)

“What a man believes may be ascertained, not from his creed, but from the assumptions on which he habitually acts.”
—George Bernard Shaw (1856–1950)